-1.186x^2+10x-8.14=0

Solution for -1.186x^2+10x-8.14=0 equation:

-1.186x^2+10x-8.14=0

a = -1.186; b = 10; c = -8.14;
Δ = b2-4ac
Δ = 102-4·(-1.186)·(-8.14)
Δ = 61.38384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-\sqrt{61.38384}}{2*-1.186}=\frac{-10-\sqrt{61.38384}}{-2.372}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+\sqrt{61.38384}}{2*-1.186}=\frac{-10+\sqrt{61.38384}}{-2.372}
$